We consider the problem of comparing deformable 3D objects represented by graphs, i.e., Triangular tessellations. We propose a new algorithm to measure the distance between triangular tessellations ...

Before using this formula, 4 hours 36 minutes needs to be converted to just hours. Do this by dividing the minutes by 60 (because there are 60 minutes in an hour). \(36 \div 60 = 0.6\) ...

To find the distance travelled, look at the area under the graph. In the first 10 seconds this is the area of the triangle, ½ × 10 s × 40 m/s = 200 m. From 10 to 20 seconds this is the area of ...