A cartesian equation of a curve is simply finding the single equation of this curve in a standard form where xs and ys are the only variables. To find this equation, you need to solve the …

It can be shown that the equation of any plane can be given by r.n=a.n, where r = xi + yj + zk, n is a direction vector normal to the plane, and a is any point vector on the plane. a can be found …

In some cases, 't' may be raised to a power in either equation. It is usually quicker to start by rearranging the lowest order equation for 't' and substituting it into the higher order equation. …

To find the Cartesian form of plane Π calculate the cross product between the vector AB and the normal vector of Π 2. (-3 , -3 , 0) x (1 , 2 , -1) = (3 , -3 , -3). We now simplify this by dividing by …

A Curve has parametric equation x=2sin(t), y= 1+cos(2t), -pi/2<=t<=pi/2. a) Find dy/dx when t=pi/3. b) Find the Cartesian equation for the curve in form y=f(x), -k<=x<=k.

Reminder - a cartesian equation is written in terms of x and y (e.g. y = 2x + 3) while parametric equations are written with x and y separately in terms of t. Example: Find the cartesian …

e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2 One-to-one online tuition can be a great way to brush up on your. Maths knowledge.

A curve has parametric equations x=2t, y=t^2. Find the Cartesian equation of the curve. x=2t --> t= x/2 ...

This Yields:1 2 = (x-2) 2 + (y+3) 2 , which is the cartesian form!we recognise this as the equation of a circle, with centre (2,-3) and radius 1. MH Answered by Mark H. • Maths tutor

A curve has the equation 6x^(3/2) + 5y^2 = 2 (a) By differentiating implicitly, find dy/dx in terms of x and y. (b) Hence, find the gradient of the curve at the point (4, 3). Answered by Matthew L.