Dec 31, 2012 · Can you use List (like ArrayList)? Or you can create a new array with bigger size, loop in old array add from index = 2. Then add new elements at index 0 and 1.

Oct 12, 2014 · I am trying to concatenate strings in Java. Why isn't this working? public class StackOverflowTest { public static void main (String args []) { int theNumber = 42; System.out.

Jan 25, 2013 · You can't. A Java array has a fixed length. If you need a resizable array, use a java.util.ArrayList<String>. BTW, your code is invalid: you don't initialize the array before using it.

May 16, 2010 · String[] where = new String[10]; and you want to add some elements to it like numbers please us StringBuilder which is much more efficient than concatenating string.

I have code that generates a random number form 0-1 3 times and I need it to be added to a variable so it turns into a binary number.So, in theory, this would run three times and possibly …

You'll want to use the static method Character.toString (char c) to convert the character into a string first. Then you can use the normal string concatenation functions.

Mar 18, 2015 · Or, if you want to do it with one String variable, it would be: String ROM = "Java Programming"; ROM = "\"" + ROM + "\""; Of course, this actually replaces the original ROM, …

Also consider java.text.MessageFormat, which uses a related syntax having numeric argument indexes. For example, String aVariable = "of ponies"; String string = MessageFormat.format("A …

I'm getting in an int with a 6 digit value. I want to display it as a String with a decimal point (.) at 2 digits from the end of int. I wanted to use a float but was suggested to use String for a ...

The Java compiler removes this incidental whitespace and keeps the essential whitespace. Then the .indent(4) method call adds four trailing spaces, essential indentation I want to add.