A compound with molecular formula C10H14 displays the following IR, 1 H NMR, 13C NMR spectra. Propose a structure for this compound. Show transcribed image text

For the following formula, C10H14, calculate the IHD and select all the types of unsaturation that might be present in the molecule based on the IHD. There are 2 steps to solve this one. Solution

Incorrect Question 14 0/0.5 pts A compound of the formula C10H 14 gave the 1H NMR spectrum shown below and exhibited three peaks in the 13C NMR spectrum.

Question: A compound with molecular formula C10H14 displays the following IR, 1H NMR, 13C NMR spectra. Propose a structure for this compound. compound. A compound with molecular formula C 10 H 14 displays the following IR, 1 H NMR, 13 C NMR spectra.

The IR and 1H NMR spectra for compound F (C10H14) are given below. Propose a structure for compound F 100 90 80 70 E 60 50 40 30 20 10 0 F, C10H14 4000 3600 3200 2800 2400 2000 1800 1600 1400 1200 1000 800 650 Wavenumber (cm-1)

Hydrocarbon A, C10H14, has a UV absorption maximum at 236 nm and gives hydrocarbon B, C1oHi8, on catalytic hydrogenation. A reacts with maleic anhydride to yield a Diels-Alder adduct. Ozonolysis of A followed by zinc/acetic aci<d treatment yields the following diketo dialdehyde: нссњењење-ссњењењен Propose a structure for ...

Hydrocarbon A, C10H14 absorbs 4 equiv. of hydrogen to give B, C10H22 when hydrogenated over a Pd/C catalyst. Treatment of A with aqueous H2SO4 and Hg(II) gives a single ketone, C, C10H16O. Oxidation of A with KMnO4 gives CO2 and the keto carboxylic acid D shown below. Propose a structure for A.

A compound with the molecular formula C10H14 gave the following 1H NMR spectrum:doublet, d 1.2singlet, d 2.3septet, d 2.8multiplet, d 7.1A possible structure for the compound is: Your solution’s ready to go!

A compound, C10H14, shows an IR peak at 825 cm-1. Its 1H NMR spectrum has peaks at delta 7.0 (4 H, broad singlet), 2.85 (1 H, septet, J=8 Hz), 2.28 (3 H, singlet), and 1.20 (6 H, doublet, J=8 Hz).

Answer to A compound, C10H14, shows an IR peak at 745 cm-1. Its. Start with calculating the sites of unsaturation to determine the number of rings or double bonds in the compound using the given formula and the compound's molecular formula C10H14.