Apr 2, 2017 · I am currently working on a simple code that will check if an user inputted String contains character (s) that are specified in the for loop. My current code. Scanner sc = new Scanner(System.in); int G = 0; int R = 0; int Y = 0; int B = 0; String S = sc.nextLine(); for (int i = 0; i < S.length(); i++) { if (S.contains("G")) { G++; } else {

Feb 28, 2022 · The simplest approach to solve this problem is to iterate a loop over the range [0, N – 1], where N denotes the length of the string, using the variable i and print the value of str [i]. Example. Method 2: Using String.toCharArray () method. In this approach, we convert string to a character array using String.toCharArray () method.

Sep 27, 2010 · How can I iterate through a string in Java? I'm trying to use a foreach style for loop. for (char x : examplestring) { //action }

Jun 27, 2021 · Scanner sc = new Scanner(System.in); System.out.println("\n\tWelcome to the Store"); System.out.print("\nPls enter the number of items you want to bill "); int n = sc.nextInt(); String name; for(int i = 1;i<=100;i++) { System.out.print("Enter the name of the item no "+i+" "); name = sc.next(); if (i == n) { break; System.out.println(); .

Example 2: Loop through each character of a string using for-each loop class Main { public static void main(String[] args) { // create a string String name = "Programiz"; System.out.println("Characters in string \"" + name + "\":"); // loop through each element using for-each loop for(char c : name.toCharArray()) { // access each character ...

Feb 2, 2024 · In the provided Java example, we illustrate how to check if a string contains a specific character using the contains() method. The process begins with the initialization of a string variable, str, and the specification of the target character, targetChar.

Jun 6, 2021 · Method 1: Using for loops. The simplest or rather we can say naive approach to solve this problem is to iterate using a for loop by using the variable ‘ i’ till the length of the string and then print the value of each character that is present in the string. Example. Time complexity is O (N) and space complexity is O (1) Method 2: Using iterators.

In this example, we will learn to check if a string contains a substring using contains() and indexOf() method in Java.

Jan 30, 2017 · If you want to use a loop, I recommend the for-each loop: boolean found = false; while (found == false) { String input = "this is a sentence, with a comma"; // read input here for (char ch: input.toCharArray()) { if (ch == ',') { found = true; } } if (found == false) { System.out.println("Error"); } }

May 11, 2024 · We can use a simple for loop to iterate over the characters of a string. This method has a time complexity of O (n), where n is the length of the string str, and a space complexity of O (1) because it only requires a single loop variable: String str = "Hello, Baeldung!"; for (int i = 0; i < str.length(); i++) { char c = str.charAt(i); .