Dec 4, 2024 · Write a MATLAB program to simulate the following difference equation 8y [n] - 2y [n-1] - y [n-2] = x [n] + x [n-1] for an input, x [n] = 2n u [n] and initial conditions: y [-1] = 0 and y …

Feb 7, 2022 · Reorder terms so y (k) is on one side of the equation. Write a for loop in MATLAB to solve this numerically after you decide how many steps in k you want to solve for.

Nov 11, 2020 · Learn more about iteration, discrete, lorenz equations, for loop, difference equations, recursive equations.

In this video, we will use a for loop to code a difference equation obtained from a discrete transfer function.

Sep 3, 2006 · Matlab doesn't like negative indexes as you seem to have noticed. But there are at least three easy ways to get around this. y1(i) = x(i)-x(i-1); y2(i) = x(i) - x0; x0 = x(i); If you want to use a loop, you can loop over i=2:N and define y (1) outside of the loop.

Dec 26, 2013 · Consider a difference equation with its initial conditions. How can I determine y (n) in Matlab? y (n-1) = 2, y (n-2) = 0 wont work (and doesn't make any sense). initial condition cannot have 'n' in it. You should specify initial condition like y …

Jan 19, 2023 · For one of my assignments I have to use loops in MATLAB to solve a difference equation. The equation has an input x (n) and initial conditions, with one condition starting at 0, and the other starting at -1. I won't post the exact question itself, as I would like to make the code myself after understanding how to do it.

Apr 5, 2022 · Steps to Solve a 2nd Order Homogeneous Difference Equation: Step 1: Let the given 2nd Order Difference Equation is: ay n+2 +by n+1 +cy n = 0 Step 2: Then, we reduce the above 2nd Order Difference Equation to its Auxiliary Equation (AE) form: ar 2 +br+c = 0 Step 3: Then, we find the Determinant of the above Auxiliary Equation (AE) by the Relation:

Jul 24, 2017 · I would like to use Matlab to compute two finite difference loops in such a manner that if we have two equations, let's say (1) and (2), it completes one step of (1) then solves (2) for one step then (1) for the next step and then (2) and so on and so forth.

Learn more about iteration, discrete, lorenz equations, for loop, difference equations, recursive equations.