Apr 28, 2018 · The documentation for set_array is very skimpy. What does it do? What range of values can it take? How does it work in conjunction with other color-related routines and data structures? On the collections docpage it is said to "Set the image array from numpy array A." It is described in the same way in the colormap API. That's all.

Oct 3, 2009 · Python has an independent implementation of array() in the standard library module array " array.array() " hence it is incorrect to confuse the two. Lists are lists in python so be careful with the nomenclature used.

For most C use cass of an array, a normal (non-fixed) list is the idiomatic python equivalent. This is an answer to the question, as it probably helps the the OP (who is transitting from C to Python) most.

@Phani correct, that's a set comprehension. a little bit more efficient than the solution in the answer, which has overhead of a function call and a generator expression.

Mar 7, 2014 · I think you're a bit confused on several things. If you're trying to chance the x & y locations, you're using the wrong method. set_array controls the color array. For the collection that scatter returns, you'd use set_offsets to control the x & y locations. (Which method you use depends on the type of artist in question.) The two vs. three arguments is coming in because artist.set_array is a ...

Nov 27, 2016 · Also note that adding items in the set from a list can prove to be very useful when you want to filter out duplicates from the list.

Whenever you are stuck in such type of problems, try to find the datatype of the element you want to convert first by using : type(my_set) Then, Use: list(my_set) to convert it to a list. You can use the newly built list like any normal list in python now.

Oct 18, 2015 · First flatten your ndarray to obtain a single dimensional array, then apply set () on it: set(x.flatten()) Edit : since it seems you just want an array of set, not a set of the whole array, then you can do value = [set(v) for v in x] to obtain a list of sets.

Jul 12, 2013 · You are storing a copy of reference to a single set in each of your list indices. So, modifying one will change the others too. To create a list of multiple sets, you can use list comprehension: sets = [set() for _ in xrange(5000)]

Aug 10, 2018 · Where are your 6 and 8 coming from in your expected set? Do you just want a set of all numbers in the flattened input list? In this case {1, 2, 3, 4}?