@Catbuilts I'm not sure, but it might help to read up on how C++ pointers work. Whereas Python tries to automatically do things the best way for you, C++ actually gives you all the options to do things in all the possible right and wrong ways, so that's a good starting point for learning what the drawbacks are of the approach that Python takes.

for python swap like this, if same indexes are provided, i.e., a==b. will python do anything? in other languages, we need to add if i==j: return to avoid any actual wasteful work. – jzleetcode Commented Sep 17, 2024 at 1:58

Apr 9, 2023 · The canonical way to swap two variables in Python is. a, b = b, a Please note than this is valid whatever the "type" of a or b is (numeric, string, tuple, object, ...). Of course, it works too if both variables reference values of different types.

If they are mutable types (list, set, dict, etc), then you could modify them in-place inside swap. However, that restricts swap to work only on mutable types. You are therefore better off returning the inputs in reversed order: def swap(s1, s2): return s2, s1 s1 = 'a' s2 = 'b' s1, s2 = swap(s1, s2) print s1, s2 # prints 'b a'

Mar 16, 2010 · Put another way, XOR swap does not create new objects in either the C99 sense ("region of data storage in the execution environment, the contents of which can represent values") or the Python sense. As noted here, a true XOR swap can "exchange the values of the variables a and b without using extra space for a temporary variable." Or empirically:

You can pass a self instance as in the above code i.e. the . operator not by var1_1=numbers.swap(var1). Instance.method() automatically implies the first argument to the method would be self . Your swapp method needs an argument.

Dec 29, 2010 · Is there any any faster way to swap two list elements in Python than L[a], L[b] = L[b], L[a] or would I have to resort to Cython or Weave or the like?

May 16, 2015 · list=[1,2,3,4,5,6] And what I want to do is to swap a number with the following one and swap the next number with the number after it. so after swapping them it would become list=[2,1,4,3,6,3] So I was wondering if there was a way to be able to swap the numbers more simply. Thank you.

You can use tuple unpacking. Tuple unpacking allows you to avoid the use of a temporary variable in your code (in actual fact I believe the Python code itself uses a temp variable behind the scenes but it's at a much lower level and so is much faster). input_seq[ix1], input_seq[ix2] = input_seq[ix2], input_seq[ix1]

The swap function is swapping the local variables x and y and not the global array. def swap(x,y): x,y=y,x This is completely wrong. You can instead do the following. Change the function body to . return y,x and call the function as a[n],a[i] = swap(a[i],a[n]) Or directly swap in-place a[n],a[i] = a[i],a[n] Or do it as you had done earlier