In Python 3 zip returns an iterator instead and needs to be passed to a list function to get the zipped ...

In Python 2, zip returns a list, to avoid creating an unnecessary list, use izip instead (aliased to zip can reduce code changes when you move to Python 3). from itertools import izip as zip So that is still (2.7):

Mar 19, 2015 · In this case, since the zip function accepts a list of iterables in order to return their aligned columns, zip(*p) passes all the items inside the p as arguments to zip function: Therefore, in this case, zip(*p) is equal to: zip([1,2,3],[4,5,6]) Also, note that since Python-3.5 you can use unpacking operators in a few other cases than in ...

Is it like a 2d for loop? why we need the zip? Can we have 2d loop with out zip function? Q2-I am not understanding how x:y works! the compile understand automatically that the definition of x and y (in "x:y") is described in the rest of the line(e.g. for loop)? P.S: I am expert in MATLAB but I am new to python and it is sometimes very ...

Feb 14, 2011 · From the itertools docs, "Like zip() except that it returns an iterator instead of a list." The I in izip() means "iterator". Python iterators are a "lazy loaded" sequence that saves memory over regular in-memory list. So, you would use itertools.izip(a, b) when the two inputs a, b are too big to keep in memory at one time.

Dec 6, 2009 · cap_dir_zip = '{}.zip'.format(root) # Opening zipfile context for current root dir. with zf.ZipFile(cap_dir_zip, 'w', zf.ZIP_DEFLATED) as new_zip: # Iterating over os.walk list of files for the current root dir. for f in files: # Defining relative path to files from current root dir. f_path = os.path.join(root, f) # Writing the file on the .zip ...

Dec 16, 2016 · I have not figured out how to use tqdm with the builtin zip object. The use case of this would be to iterate over two corresponding lists with a console progressbar. For example, I would expect this to work: for _, _ in tqdm(zip(range(10), range(10))): sleep(0.1) but the progressbar printed to the console in this case is not correct:

Nov 10, 2013 · Also @luke14free for the second answer I think you mean [list(i) for i in zip(*a)] as zip(*a) already produces tuples. edit: I agree with agf, not sure why you are getting numpy involved here when you don't need to. zip(*a) with a cast to list is a much more elegant(and correct!) solution. –

Aug 10, 2010 · from zipfile import ZipFile ZipFile("YOURZIP.zip").extractall("YOUR_DESTINATION_DIRECTORY") The directory where you will extract your files doesn't need to exist before, you name it at this moment. YOURZIP.zip is the name of the zip if your project is in the same directory. If not, use the PATH i.e : C://....//YOURZIP.zip

Jun 15, 2012 · I have a list of names: ['john smith', 'sally jones', 'bob jones'] I want to build a dict in the following format: {'john smith': [], 'sally jones': [], 'bob jones ...