Apr 26, 2014 · I wanted to use MOD function in SQL Server 2008R2 and followed this link but still got the message: 'MOD' is not a recognized built-in function name. DECLARE @m INT SET @m = MOD(321,11) SELECT @m Error: Msg 195, Level 15, State 10, Line 2 'MOD' is not a recognized built-in function name. Why I can't use this function from the link above?

Oct 7, 2013 · How do you use MOD in WHERE clause? I am wanting to update even or odd rows based on ID. I am wanting to update even or odd rows based on ID. update employee set respstr1 = 'EP' where mid = 7246 and (mod(id/2) = 1)

Aug 13, 2017 · MySQL, SQL Server, PostgreSQL, SQLite support using the percent sign as the modulus: ... For Oracle, you ...

Jun 10, 2016 · Simple question in regards to MOD alternative in SQL Server. I know SQL Server MOD is written as % but that usually requires a number % number. My question is how can I use the % when I have these clauses in the code: SELECT NULL, LeagueID, COUNT(1), 1, COUNT(1), 1 FROM Team GROUP BY LeagueID HAVING MOD( COUNT(1), 2 ) > 0 OR

Jul 23, 2018 · So I would write this into a subquery and then just put a parameter on the main query for (Where Order >= 3), however, it appears that the % Modulus Operator is throwing off errors. It gets a little dicey for me as I don't have access to the production DB and querying the table thorough a Cognos 11 SQL pass-through.

Mar 27, 2013 · It sounds like this is what you're looking for -- use the % operator to perform a Mod: select a % 2, sum(b) from yourtable group by a % 2 Condensed SQL Fiddle Demo. To apply this to your query, try this:

I'm having trouble replicating the mod function in SQL sever. In excel, mod (-3, 7) = 4. But in SQL, -3 % 7 = -3 Am I using % wrong, or does SQL do mod differently?

Jun 27, 2014 · MOD(13,5): returns 3 whereas, REMAINDER (13,5) returns -2. A simple way to understand the difference is that MOD uses the floor function therefore it counts the occurrence of the second number within the first and returns what is left to complete the first number i.e. 2(5) gives 10 adding 3 gives 13 therefore MOD(13,5)=3

The modulus function in Microsoft SQL Server only works on certain data types. According to the MSDN Article [1] on the modulus operator, you normally would use modulus like this... dividend % divisor dividend Is the numeric expression to divide. dividend must be a valid expression of any one of the data types in the integer and monetary data ...

I need only even or odd items, so I find modulus operation and this doesn't works SELECT * FROM table ORDER BY id WHERE MOD (num, 2) = 1 ASC; Please help me, I'm noob in sql, as I haven't done mu...