Oct 17, 2023 · So I am just wondering as I continue solving the Leetcode problems, Is there any helper functions from the Python library that could help me based on the topics (array, hashing, DP, graph, interval, etc)?

Apr 4, 2022 · Hi everyone, I'm practicing Leetcode for SWE interviews. While working on Leetcode #79, Word Search, I realized the solution I followed used a nested, DFS function rather than a DFS method in the Solution class.

May 12, 2022 · They're looking for readability on top of efficacy for code, and helper functions make everything more readable. Unless it's for something that has to be hyper-optimized like a graphics engine, I doubt you would ever be worse-off using helper functions.

Mar 16, 2017 · A "helper function" is a function you write because you need that particular functionality in multiple places, and because it makes the code more readable. A good example is an average function.

Nov 3, 2024 · Below are some assorted tips to make python leetcode solutions nicer. Python uses exclusively for .. in loops, rather than the traditional C-style for (int i = 0; i < arr.length; i++) loops. If you have a loop that looks like. elem = arr[i] print(elem) you should replace it with for elem in arr. If you do need the index, use enumerate(..)

P A H N A P L S I I G Y I R And then read line by line: "PAHNAPLSIIGYIR" Write the code that will take a string and make this conversion given a number of rows: string convert(string s, int numRows); I used a helper function approach after realizing that the "Grid" needs to be updated in the same manner over and over again

Solve the Equation - Solve a given equation and return the value of 'x' in the form of a string "x=#value". The equation contains only '+', '-' operation, the variable 'x' and its coefficient. You should return "No solution" if there is no solution for the equation, or "Infinite solutions" if there are infinite solutions for the equation.

Make The String Great - Given a string s of lower and upper case English letters. A good string is a string which doesn't have two adjacent characters s [i] and s [i + 1] where: * 0 <= i <= s.length - 2 * s [i] is a lower-case letter and s [i + 1] is the same letter but in upper-case or vice-versa.

Aug 30, 2020 · def helper(self,arr,left,right,k): if (left>=right): return . p = self.partition(arr,left,right) print("p is now "+str(p)) if (p==len(arr)-k): return int(arr[p]) self.helper(arr,left,p-1,k) …

Jul 15, 2023 · When I try to implement a solution without using a helper, it fails some test cases, despite being similar in function. Why is this? Below the accepted answer and my code without the helper. Accepted solution: def isBalanced(self, root): def dfs(root): if not root: return [True, 0] left = dfs(root.left) right = dfs(root.right)