shape is a tuple that gives you an indication of the number of dimensions in the array. So in your case, since the index value of Y.shape[0] is 0, your are working along the first dimension of …

Shape n, expresses the shape of a 1D array with n items, and n, 1 the shape of a n-row x 1-column array. (R,) and (R,1) just add (useless) parentheses but still express respectively 1D …

Jan 7, 2018 · x[0].shape will give the Length of 1st row of an array. x.shape[0] will give the number of rows in an array. In your case it will give output 10. If you will type x.shape[1], it will …

Sep 9, 2013 · When reshaping an array, the new shape must contain the same number of elements as the old shape, meaning the products of the two shapes' dimensions must be …

Nov 30, 2017 · yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; And you can get the (number of) dimensions of your array using yourarray.ndim or …

Oct 19, 2017 · P.S.: Note that tensor.shape is an alias to tensor.size(), though tensor.shape is an attribute of the tensor in question whereas tensor.size() is a function. Share Improve this answer

Feb 1, 2021 · Then the shape of the object holds a tuple (rows, columns, channels). (height,width)=img.shape[:2] is an example of tuple unpacking, with it you extract the rows and …

May 24, 2016 · So maybe df.shape[0] + df.shape[1] is slower than len(df.index) + len(df.columns). Still, performance-wise, the difference should be negligible except for a giant giant 2D …

Jun 9, 2015 · To complement Harlan's answer, here is a references for the available shapes - start from 0 at bottom left and read right then up (10y + x):

ValueError: Shape of passed values is (5,), indices imply (5, 5) I've been wrestling with this for a few days now and nothing seems to work. What is interesting is that when I change . def …